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-6x^2-12x=-11
We move all terms to the left:
-6x^2-12x-(-11)=0
We add all the numbers together, and all the variables
-6x^2-12x+11=0
a = -6; b = -12; c = +11;
Δ = b2-4ac
Δ = -122-4·(-6)·11
Δ = 408
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{408}=\sqrt{4*102}=\sqrt{4}*\sqrt{102}=2\sqrt{102}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-2\sqrt{102}}{2*-6}=\frac{12-2\sqrt{102}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+2\sqrt{102}}{2*-6}=\frac{12+2\sqrt{102}}{-12} $
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